(玩電子) 電子技術學習與研究
當前位置:單片機教程網 >> MCU設計實例 >> 瀏覽文章

8*8LED點陣顯示0-9

作者:佚名   來源:本站原創   點擊數:x  更新時間:2012年05月10日   【字體:
電路很簡單8*8點陣的行和列分別接在單片機的p3口和p1口,我測試成功.
#include <AT89X52.H>
unsigned char code tab[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f};
unsigned char code digittab[10][8]={       {0x00,0x00,0x3e,0x41,0x41,0x41,0x3e,0x00},     //0
                                    {0x00,0x00,0x00,0x00,0x21,0x7f,0x01,0x00},     //1
                                    {0x00,0x00,0x27,0x45,0x45,0x45,0x39,0x00},    //2
                                    {0x00,0x00,0x22,0x49,0x49,0x49,0x36,0x00},    //3
                                    {0x00,0x00,0x0c,0x14,0x24,0x7f,0x04,0x00},     //4
                                    {0x00,0x00,0x72,0x51,0x51,0x51,0x4e,0x00},    //5
                                    {0x00,0x00,0x3e,0x49,0x49,0x49,0x26,0x00},    //6
                                    {0x00,0x00,0x40,0x40,0x40,0x4f,0x70,0x00},     //7
                                    {0x00,0x00,0x36,0x49,0x49,0x49,0x36,0x00},    //8
                                    {0x00,0x00,0x32,0x49,0x49,0x49,0x3e,0x00}     //9
                                    };
unsigned int timecount;
unsigned char cnta;
unsigned char cntb;
void main(void)
{
  TMOD=0x01;
  TH0=(65536-3000)/256;
  TL0=(65536-3000)%256;
  TR0=1;
  ET0=1;
  EA=1;
  while(1)
    {;
    }
}
void t0(void) interrupt 1 using 0
{
  TH0=(65536-3000)/256;
  TL0=(65536-3000)%256;
  P3=tab[cnta];
  P1=digittab[cntb][cnta];
  cnta++;
  if(cnta==8)
    {
      cnta=0;
    }
  timecount++;
  if(timecount==333)
    {
      timecount=0;
      cntb++;
      if(cntb==10)
        {
          cntb=0;
        }
    }
}
 
發表評論】【告訴好友】【收藏此文】【關閉窗口

文章評論

相關文章

沙滩排球小游戏